brizz1502

brizz1502

01.12.2021 •

Mathematics

GCF of 42 and 7 using distributive porperty

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Ответ:

trinitieu66

09.05.2023

The test statistics is z = -1.56

The p-value is p-value = 0.05938

Step-by-step explanation:

From the question we are told

The West side sample size is n_1 = 578

The number of residents on the West side with income below poverty level is k = 76

The East side sample size n_2=688

The number of residents on the East side with income below poverty level is u = 112

The null hypothesis is H_o : p_1 = p_2

The alternative hypothesis is H_a : p_1 < p_2

Generally the sample proportion of West side is

$\^{p} _1 = \frac{k}{n_1}$

=> $\^{p} _1 = \frac{76}{578}$

=> $\^{p} _1 = 0.1315$

Generally the sample proportion of West side is

$\^{p} _2 = \frac{u}{n_2}$

=> $\^{p} _2 = \frac{112}{688}$

=> $\^{p} _2 = 0.1628$

Generally the pooled sample proportion is mathematically represented as

$p = \frac{k + u}{ n_1 + n_2 }$

=> $p = \frac{76 + 112}{ 578 + 688 }$

=> p =0.1485

Generally the test statistics is mathematically represented as

$z = \frac{\^ {p}_1 - \^{p}_2}{\sqrt{p(1- p) [\frac{1}{n_1 } + \frac{1}{n_2} ]} }$

=> $z = \frac{ 0.1315 - 0.1628 }{\sqrt{0.1485(1-0.1485) [\frac{1}{578} + \frac{1}{688} ]} }$

=> z = -1.56

Generally the p-value is mathematically represented as

p-value = P(z < -1.56 )

From z-table

P(z < -1.56 ) = 0.05938

So

p-value = 0.05938

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