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sauloro06
14.07.2019 •
Mathematics
Geometry math question no guessing and show work you
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Ответ:
We are given, ∠AFD =90° AND ∠AFB=31°
∠AFD=∠AFB+∠BFC+∠CFD
FROM FIGURE, ∠AFB=∠CFD
90°=∠AFB+∠BFC+∠AFB
90=31+∠BFC+31
90=62+∠BFC
∠BFC=90-62=28°
∠BFC=∠DFE (AS GIVEN IN FIGURE)
SO ∠BFC=28° (OPTION D)
Ответ:
Part 1
Let the consecutive multiples be 5x and 5x + 5
ATQ
5x + 5x + 5 = 55
10x = 55 - 5
10x = 50
x = 5
Answer is 25 and 30
Part 2
Let the number be x , x + 1, x + 2
ATQ
x + x + 1 + x + 2 = 93
3x + 3 = 93
3x = 93 - 3
x = 90/3
x = 30
The integers are 30,31 and 32
Part 3
Let the number be x
ATQ
3x - 5 = 10
3x = 10 + 5
x = 15/3
x = 5
The number is 5
Answered by Gauthmath must click thanks and mark brainliest