Geometry need answers to 2,3,4, and 5

When club members will sell 2 cakes, sales will cover expenditure . sales for 2 cakes is $28 and expenditure for 2 cakes is $28. Required equations are  as follows  

x = 14y (equation for sale)  

x = 3y + 22 (equation for expenditure).

Solution:

Need to write a system of equations to describe given situation.

Given that  

Members of cooking club are making cakes to sell at street fair.

Selling price of a piece of cake = $14

Cost of booth at the fair = $22

Cost of ingredient for 1 cake = $3

we need to find a point where expenditure is equal to sale.

let say number of cakes be represented by variable y

So selling price of y cakes = selling price of 1 cake multiplied by y = 14 x y = 14y

COST OF y CAKES

Cost of ingredient of y cakes = cost of ingredient of 1 cake x y = 3 x y = 3y

Cost of the booth = $22

total cost of y cakes = Cost of ingredient + cost of booth = 3y + 22

Expenditure will cover when total cost is equal to selling price  

=> 14y = 3y + 22

On solving the above equation for y

=> 14y – 3y = 22

=> 11y = 22

=> y = 2  

So when club members will sell 2 cakes

Sale = 2 x 14 = $28

Expenditure (cost) = (3)2 + 22 = $28

So after selling 2 cakes expenditure will get covered.

Also given that club sale and expenditure will be $x once they have sold y cakes

=> x = 14y (equation for sale)  

And x = 3y + 22 (equation for expenditure).