Mathematics: Geometry the diagonals of a kite are in the ratio of 3: 2. the area of the kite is 27 cm^2 . find the length of both diagonals. (hint: let the lengths of the diagonals be 3x and 2x)how do i do this?

Geometry the diagonals of a kite are in the ratio

Ответ:

lcidsjay

31.12.2021

$A=27 \ cm^2 \\ \\ d_{1}=3x , \ \ d_{2} = 2x \\ \\ S=\frac{1}{2}\cdot d_{1}\cdot d_{2}\\ \\27 = \frac{1}{2}\cdot 3x \cdot 2x \\ \\ 3x^2 = 27 \ \ /:3$

$x^2 = 9 \\ \\3x=x=\sqrt{9}\\ \\x=3 \ cm \\ \\ d_{1}=3x = 3*3 =9 \ cm \\ \\d_{2}=2x=2*3 = 6 \ cm \\ \\ Answer : \\ The \ length \ of \ the \ diagonal \ is: \ d_{1}= 9 \ cm \ and \ d_{2}= 6 \ cm$

Geometry the diagonals of a kite are in the ratio of 3: 2. the area of the kite is 27 cm^2 . find th

Geometry the diagonals of a kite are in the ratio of 3: 2. the area of the kite is 27 cm^2 . find th

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Ответ:

Christiancameron1234

30.04.2023

Mathematics

If you cannot divide the numerator and denominator by the same number, then you are done dividing and the fraction is in simplest form.

EXAMPLE:
4/8 = 2/4 = 1/2
I divided 4/8 by 2 and I divided 2/4 by 2 to get 1/2, which the numerator and denominator cannot be divided by the same number. So I'm done.

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Geometry
the diagonals of a kite are in the ratio of 3: 2. the area of the kite is 27 cm^2 . find the length of both diagonals. (hint: let the lengths of the diagonals be 3x and 2x)
how do i do this?

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