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Let us first jot down all the data given in the question;

Number of low quality computers (LQ) = 72

Number of medium quality computers (MQ) = 112

Number of high quality computers (HQ) = 711

∴ Total number of computers found in a random sample = 72 + 112 + 711 = 895.

∴ To find the probability of purchase for each category of computers, we use the following formula;

So,

P(LQ) = 72/895 = 0.08

P(MQ) = 112/895 = 0.125

P(HQ) = 711/895 = 0.794

Ans) Probability of purchase of  a low quality computer, a medium quality computer, and a high quality computer are 0.08, 0.125, and 0.794 respectively

A similar answer can be found here:-

1/117,1/112,1/72

just make it a faction by adding one as the numeerator

x = 2 , y = -2

Step-by-step explanation:

Solve the following system:

{5 x - y = 12 | (equation 1)

3 x + y = 4 | (equation 2)

Subtract 3/5 × (equation 1) from equation 2:

{5 x - y = 12 | (equation 1)

0 x+(8 y)/5 = (-16)/5 | (equation 2)

Multiply equation 2 by 5/8:

{5 x - y = 12 | (equation 1)

0 x+y = -2 | (equation 2)

Add equation 2 to equation 1:

{5 x+0 y = 10 | (equation 1)

0 x+y = -2 | (equation 2)

Divide equation 1 by 5:

{x+0 y = 2 | (equation 1)

0 x+y = -2 | (equation 2)

Collect results:

{x = 2 , y = -2