jayme2407
20.03.2020 •
Mathematics
Give a combinatorial proof that if n is a positive integer then ∑n k =0 k2 (n k ) = n(n + 1)2n−2.[Hint: Show that both sides count the ways to select a subset of a set of n elements together with two not necessarily distinct elements from this subset. Furthermore, express the righthand side as n(n − 1)2n−2 + n2n−1.]
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Ответ:
there is only 1 solution.
Step-by-step explanation:
We can solve the equation to find it's number of solutions, but we already know it only has 1 solution because it is a linear equation (y is raised to the first power).
3y + 5 − 2y = 11
y + 5 = 11
y = 6
This confirms that there is only 1 solution.