Give the function f(x)=2e^x, find f(x) if x=3

To answer this, substitute 3 to x in the given function. The final function would be, f(x) = 2e^3. e is a constant with a value of 2.7183. In this function, only the e or 2.7183 is raise to exponent 3. Thus, the value of the function is 40.1711. 

70 times

Step-by-step explanation:

5 consecutive even integers: 2n, 2n+2, 2n+4, 2n+6, 2n+8 for any integer n The sum of the two smallest of five consecutive even integers is 50 less than the sum of the other three integers: 2n + 2n+2 = 2n+4 + 2n+6 + 2n+8 - 504n + 2 = 6n -3234 = 2nn = 17 The smallest integer in our sequence is 2n = 2*17 = 34 Check:2n + 2n+2 = 2n+4 + 2n+6 + 2n+8 - 5034 + 36 = 38 + 40 + 42 - 5070 = 120 - 5070 = 70