Mathematics: Given a polynomial and one of its factors bother main factors 9x^3 + 20x^2 - 68x - 16; (x+4)

Given a polynomial and one of its factors bother

solisemily62

28.01.2022

9x+2 and x-2.

Step-by-step explanation:

Given the polynomial 9x^3 + 20x^2 - 68x - 16

If one of the factors is x+4, then to obtain the other factor, we divide the polynomial by the known factor.

$\dfrac{9x^3 + 20x^2 - 68x - 16}{x+4} =9x^2-16x-4$

Next, we factorize our result

$9x^2-16x-4=9x^2-18x+2x-4\\=9x(x-2)+2(x-2)\\=(9x+2)(x-2)$

Therefore, the other factors of the polynomial are 9x+2 and x-2.

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itzia00

21.09.2022

The square root is √24 = 2√6.

Step-by-step explanation:

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