Given: abcd is a ∥-gram; de ∩ ab =f prove: △adf∼△cde

By AA similarity

Step-by-step explanation:

We have been given that ABCD is a parallelogram

So, by the property of parallelogram AB ||CD and FD is cutting the line BC

Hence, FD is transverse line. In transverse line alternate angles are equal.

Therefore, ∠AFD=∠EDC  (alternate interior angles)

And ∠FAD=∠ECD (opposite angles in parallelogram)

Therefore, by AA similarity △ADF∼△CDE

Hello. Please add an image or screenshot, or provide the coordinates of GFE. When you do, I will get back to you.

Step-by-step explanation: