jzoda7318
26.11.2019 •
Mathematics
given: △ace,
bd∥ae
prove: ba/cb=de/cd
Solved
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Ответ:
first box
m<1 = m<4 and m<2 = m<3
second box
AA theorem
third box
BA/CB = DE/CD
Ответ:
D(–5,3) and E(–5,1)
Step-by-step explanation:
i just took the test!