Mathematics: Given f(x)=1/(x+5) and g(x)=x-2 what are the restrictions of the domain of f(g(x))

Given f(x)=1/(x+5) and g(x)=x-2 what are the

cexe468

13.03.2022

F(x) = 1/(x+5)
g(x)= x-2
f(g(x))= 1/(x-2+5)= 1/(x+3)

Domain of f(g(x)) - all real numbers except x= - 3.
(-∞, - 3)U(-3, +∞)

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lnbrown5633

13.03.2022

domain is

R-{-3}

Step-by-step explanation:

Given that

$f(x) = \frac{1}{x+5}$

and g(x) = x-2

We find that domain of f(x) is R-{-5} and g(x) has all real numbers as domain

$f{g(x)}=f(x-2)\\=\frac{1}{x-2+5} \\=\frac{1}{x+3}$

Thus we find the composition of function has x+3 in denominator

Hence domain is

R-{-3}

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dogisreallyeggroll

14.03.2021

Step-by-step explanation:

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