Given f(x)=ax+b/b-ax
what is the root of f(x)?

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Ответ:

QueenNerdy889

27.12.2022

Mathematics

Hi there!

We can begin by calculating the segment AC using the Pythagorean theorem.

AC^2 = AB^2 + BC^2

Plug in the given values:

$AC^2 = 6^2 + 7^2\\\\AC^2 = 85\\\\AC = 9.22 cm$

Now, we can construct a new triangle using AM, MT, and AT.

Since "M" is the midpoint of AC:

AC = 2AM

9.22 = 2AM

AM = 4.61 cm

AT is the hypotenuse in this instance and AM is one of the legs, so:

$AT^2 = AM^2 + MT^2\\\\10^2 = 4.61^2 + MT^2\\\\78.75 = MT^2\\\\MT = 8.87 \approx \boxed{8.9 cm}}$

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Given f(x)=ax+b/b-ax what is the root of f(x)?