Mathematics: Given g(x)= root x-4 and h(x) = 2x-8 what is g(h(10))

its AStep-by-step explanation:i just did it swag...

Given g(x)= root x-4 and h(x) = 2x-8 what is g(h(10))

jjace0016

10.01.2022

The value of g(h(10)) is $2 \sqrt{2}$

Step-by-step explanation:

Given that,

$g(x)=\sqrt{(x-4)}$ and h(x) = 2x-8

To find g(h(10)) first find h(10) that implies

h(x) = 2x-8

$h(10)=(2 \times 10)-8$

h(10) = 20 - 8

h(10) = 12

Now, g(h(10)) = g(12)

$g(x)=\sqrt{(x-4)}$

$g(12)=\sqrt{(12-4)}$

$g(12)=\sqrt{8}$

$\sqrt{8}$ Can be written as $=\sqrt{2 \times 2^{2}}$

$g(12)=\sqrt{2} \times \sqrt{2^{2}}$

$g(12)=2 \sqrt{2}$

$\therefore$ $g(h(10))=2 \sqrt{2}$

Therefore $g(h(10))=2 \sqrt{2}$ for the Given g(x) = root x-4 and h(x) = 2x-8.

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