Given:Quadrilateral ABCD has vertices at A(-3,-2), B(0,3), C(6,5), and D(9,2) Prove: Quadrilateral ABCD is a trapezoid.

Given:
2x + 3y = 1470

convert to slope intercept form to find the slope and y-intercept.

In the slope intercept form: y = mx + bm is the slope and b is the y-intercept.

2x + 3y = 1470
3y = -2x + 1470
y = -2x/3 + 1470/3
y = -2x/3 + 490

slope is -2/3
y intercept is 490

2x + 3y = 1593
3y = -2x + 1593
y = -2x/3 + 1593/3
y = -2x/3 + 531

slope is -2/3
y intercept is 531

Both slopes are the same, the y-intercept increased by 41

If the trend is the same, I can assume that the third month will have this expression.

2x + 3y = 1716

2x + 3y = 1716
3y = -2x + 1716
y = -2x/3 + 1716/3
y = -2x/3 + 572

slope is -2/3
y intercept is 572.

I got the 1716 by multiplying 41 by 3 and adding the product to 1593.