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SkyMelvin
19.01.2021 •
Mathematics
Given that 4704/m = n^2, where m and n are whole numbers and n is as large as possible, find the value of m and of n
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Ответ:
n=28,m=6
Step-by-step explanation:
Rearrange to give 4704 = m * n^2
Express 4704 in its prime factorisation:
2^5 * 3^1 * 7^2
We know that n must be as large as possible and, because it is squared, be the even numbers.
We get n^2 = 2^4 * 7^2 so n = 2^2*7 = 28
m is the leftovers
2^1*3 = 6
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Johnathan is rich...
Step-by-step explanation: