jorgefrom584
21.07.2020 •
Mathematics
Given that sin x equals to a over b then what is tan x
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Ответ:
tan x = a/sqrt(b^2 - a^2)
Step-by-step explanation:
sin x = a/b = opp/hyp
tan x = opp/adj
adj^2 + opp^2 = hyp^2
adj^2 + a^2 = b^2
adj = sqrt(b^2 - a^2)
tan x = a/sqrt(b^2 - a^2)
Ответ:
150
Step-by-step explanation:
If u get it wrong sorry :(