Given the following geometric sequence, find the common ratio. {0.45, 0.9, 1.8, ...}

FG = 28 meters

Step-by-step Explanation:

==>A design ABCD and its dilated photocopy EFGH.

Length of side AB = 17m

BC = 14m

DA:HE = 1:2

==>Required:

Length of side FG on the photocopy EFGH, in meters.

==>Solution:

Dilation of design ABCD would, upon transformation would produce a photocopy EFGH that is similar. Thus, ABCD ~ EFGH

Since ABCD is similar to EFGH, it means the ratio of their corresponding sides would be the same, and also have the same scale factor.

Therefore, it means DA:HE = BC:FG

Therefore, let's find length of side FG of the photocopy using the ratio1:2 that is given for DA:HE, which would also apply as the scale factor or ratio for all other corresponding sides.

Thus,

1:2 = BC:FG

1:2 = 14:FG

1/2 = 14/FG

Cross multiply to solve for FG

1×FG = 14×2

FG = 28 meters