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31.03.2021 •
Mathematics
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Ответ:
thx man your a good guy
Step-by-step explanation:
Ответ:
we know that
the volume of the oblique pyramid with a square base is equal to
V=\frac{1}{3}BhV=
3
1
Bh
where
B is the area of the base
h is the height of the pyramid
In this problem
The area of the base is
B=EF^{2}\ units^{2}B=EF
2
units
2
h=AB\ unitsh=AB units
The two formulas to calculate h are
Applying the Pythagoras Theorem
h^{2}=AC^{2}-CB^{2}h
2
=AC
2
−CB
2
> h=\sqrt{AC^{2}-CB^{2}}h=
AC
2
−CB
2
h^{2}=AD^{2}-DB^{2}h
2
=AD
2
−DB
2
> h=\sqrt{AD^{2}-DB^{2}}h=
AD
2
−DB
2
therefore
the answer is
AB and EF
AC, CB and EF
AD, DB and EF