Graph the line passing through (6,−2) whose slope is m=−3

Step-by-step explanation:

When you know the slope m of a line and a point (x₀,y₀) on the line, you can write an equation for the line in "point-slope" form:

y-y₀ = m(x-x₀)

In your case,

y+2 = -3(x-6)

The line is easier to graph if you rearrange the equation to solve for y:

y = -3x+16

You know that (0,16) is one of the points on the line.

Plot the two points that you know, (6,-2) and (0,16), then draw a line through them.

The correct option is;

Yes, the line should be perpendicular to one of the rectangular faces

Step-by-step explanation:

A perpendicular cross-section of a triangular prism resting on a rectangular face will have a triangular cross-section section an either side of the line of the cross-section, therefore we have;

Given that the triangular prism is lying on one of the rectangular faces, the perpendicular cross-section will be represented by a line drawn along the slant height of the triangular prism, therefore the correct option is yes, the line should be perpendicular to one of the rectangular faces.