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aramirez4785
17.12.2019 •
Mathematics
Guest ages at a ski mountain resort typically have a right-skewed distribution. assume the standard deviation (σ) of age is 14.5 years. from a random sample of 40 guests the sample mean is 36.4 years. calculate a 99 percent confidence interval for µ, the true mean age of guests.
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Ответ:
(30.49 years, 42.31 years)
Step-by-step explanation:
The formula to find the confidence interval is given by :-
, where
= Sample mean
z* = Critical value.
n= Sample size.
As per given , we have
n= 40
We know that the critical value for 99% confidence interval : z* = 2.576 (By z-table)
A 99 percent confidence interval for µ, the true mean age of guests will be :
∴ a 99 percent confidence interval for µ, the true mean age of guests = (30.49 years, 42.31 years)
Ответ:
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