Han has a thin rectangular sheet of paper. Its area is 450 square inches. He folds it into thirds, and then he folds the resulting rectangle into thirds again. Han believes that after two rounds of folding, the visible area of the folded paper will be 150 square inches, or one-third of the original area. Do you agree

Since Han folds the paper into thirds, and again in thirds, then the statement believed by Han is wrong since his statement says that resultant folding's area is one third which means only one round of folding happened which isn't true.

Thus, No, it is not true that visible area of folded paper is 150 sq. inches(or one third of original area).

The visible area would be divided into three parts and only one part would be visible. Thus, one of third of the paper is visible only, or we can say that:

By same above logic, we will have:

Thus, the resultant folded paper's visible area would be 50 sq inch which is one-ninth of the original area.

Thus, No, it is not true that visible area of folded paper is 150 sq. inches(or one third of original area).

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Step-by-step explanation:

Here, the initial area of the sheet  = 450 sq inches.

After folding the sheet in to thirds ONCE :

The area of the each rectangle so formed   =   =  150 sq. inches

So, the area of each rectangle  = 150 sq inches

After folding the sheet in to thirds TWICE :

The area of the each rectangle so formed   =   =  50 sq. inches

So, the area of each rectangle  = 50 sq inches

So, as we can see after two rounds of folding, we get in total 9 rectangles.

The area of each rectangle so formed   =   50 sq inches.

50 sq inches  = of the total area.

Hence, the given statement is not true.

Step-by-step explanation: