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patrickwilson
03.07.2019 •
Mathematics
He campus of a college has plans to construct a rectangular parking lot on land bordered on one side by a highway. there are 720 ft of fencing available to fence the other three sides. let x represent the length of each of the two parallel sides of fencing. a rectangle has width x. x x (a) express the length of the remaining side to be fenced in terms of x. (b) what are the restrictions on x? (c) determine a function a that represents the area of the parking lot in terms of x. (d) determine the values of x that will give an area between 20 comma 000 and 40 comma 000 ftsquared. (e) what dimensions will give a maximum area, and what will this area be?
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Ответ:
(a) 720 -2x
(b) 0 ≤ x ≤ 360
(c) A = x(720 -2x)
(d) (30.334, 68.645) ∪ (291.355, 329.666) (two disjoint intervals)
(e) x = 180 ft, the other side = 360 ft; total area 64,800 ft²
Step-by-step explanation:
(a) The two parallel sides of the fenced area are each x feet, so the remaining amount of fence available for the third side is (720 -2x) ft. Then ...
length = 720 -2x
__
(b) The two parallel sides cannot be negative, and they cannot exceed half the length of the fence available, so ...
0 ≤ x ≤ 360
__
(c) Area is the product of the length (720-2x) and the width (x). The desired function is ...
A = x(720 -2x)
__
(d) For an area of 20,000 ft², the values of x will be ...
20000 = x(720 -2x)
2x² -720x +20000 = 0
x = (-(-720) ±√((-720)² -4(2)(20000)))/(2(2)) = (720±√358400)/4
x = 180 ±40√14 = {30.334, 329.666} . . . feet
For an area of 40,000 ft², the values of x will be ...
x = 180 ±20√31 ≈ {68.645, 291.355} . . . feet
The values of x producing areas between 20,000 and 40,000 ft² will be values of x in the intervals (30.334, 68.645) or (291.355, 329.666) feet.
__
(e) The vertex of the area function is at the axis of symmetry: x = 180. The corresponding dimensions are ...
180 ft × 360 ft
and the area of that is 64,800 ft².
Ответ:
The scale factor of dilation is One-third
Step-by-step explanation:
If point (x , y) is dilated by a scale factor k, then its image is (kx , ky)
If 0 < k < 1, then kx < x and ky < yIf k > 1, then kx > x and ky > y∵ The vertices of the square ABCD are:
A = (-21 , 18)
B = (-12 , 18)
C = (-12 , 9)
D = (-21 , 9)
∵ A' = (-7 , 6)
∴ (kx , ky) = (-7 , 6)
∵ x , y are the coordinates of Point A
∵ x = -21 and kx = -7
∴ k(-21) = - 7
- Divide both sides by -21
∴ k =![\frac{1}{3}](/tpl/images/0508/7442/5506e.png)
∵ y = 18 and ky = 6
∴ k(18) = 6
- Divide both sides by 18
∴ k =![\frac{1}{3}](/tpl/images/0508/7442/5506e.png)
∵ C' = (-4 , 3)
∴ (kx , ky) = (-4 , 3)
∵ x , y are the coordinates of Point C
∵ x = -12 and kx = - 4
∴ k(-12) = - 4
- Divide both sides by -12
∴ k =![\frac{1}{3}](/tpl/images/0508/7442/5506e.png)
∵ y = 9 and ky = 3
∴ k(9) = 3
- Divide both sides by 9
∴ k =![\frac{1}{3}](/tpl/images/0508/7442/5506e.png)
∴ The scale factor of dilation is One-third