Mathematics: He u don’t have to answer this

He u don’t have to answer this

Ответ:

AJRL2005

06.11.2020

Mathematics

Step-by-step explanation:

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Ответ:

leah5981

01.10.2022

Mathematics

The cross-section of the beam with a parabola will more or less look like the one below, check picture below

now, if we take the 3 to be the focus point, and we put the parabola at the origin, like the second picture below

then we can do something like

$\bf \textit{parabola vertex form with focus point distance}\\\\
\begin{array}{llll}
(y-{{ k}})^2=4{{ p}}(x-{{ h}}) \\\\
\boxed{(x-{{ h}})^2=4{{ p}}(y-{{ k}})} \\
\end{array}
\qquad 
\begin{array}{llll}
vertex\ ({{ h}},{{ k}})\\\\
{{ p}}=\textit{distance from vertex to }\\
\qquad \textit{ focus or directrix}
\end{array}\\\\
-----------------------------\\\\
\begin{cases}
p=3\\
h=0\\
k=0
\end{cases}\implies (x-0)^2=4(3)(y-0)\implies x^2=12y
\\\\\\
\boxed{\cfrac{1}{12}x^2=y}$

Amanufacturer is designing a flashlight. for the flashlight to emit a focused beam, the bulb needs t

Amanufacturer is designing a flashlight. for the flashlight to emit a focused beam, the bulb needs t

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He u don’t have to answer this

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