Mathematics: Help ASAP. Thank you! Find the area of the shaded region. 80° 5 cm A=[?] cm2

Help ASAP. Thank you! Find the area of the shaded

Ответ:

alyssashae1818

11.04.2021

Step-by-step explanation:

$\text{The area shaded outside of the triangle is}\\ \\ A=\frac{\pi r^2\theta}{360},\ r=5,\ \theta =80^o\\ \\ A=\frac{50\pi}{9}\\ \\ \text{Then we must add the area of the shaded triangle.}\\ \\ A=\frac{bh}{2}\\ \\ \frac{b}{2}=5sin40^o\\ \\ h=5cos40^o\\ \\ A=25sin40^o(cos40^o)\\ \\ \text{Total area is}\\ \\ A=\frac{50\pi }{9}+25sin40^o(cos40^o)\\ \\ A\approx 29.8cm^2$

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Ответ:

katieleeisaacs8368

04.05.2022

Mathematics

1 x -3 = -3

a positive x a negative = a negative.

1053^48= 1053 x 1053 x 1053 x 1053 x 1053 x 1053 x 1053 x 1053 x 1053 x 1053 x 1053 x 1053 x 1053 x 1053 x 1053 x 1053 x 1053 x 1053 x 1053 x 1053 x 1053 x 1053 x 1053 x 1053 x 1053 x 1053 x 1053 x 1053 x 1053 x 1053 x 1053 x 1053 x 1053 x 1053 x 1053 x 1053 x 1053 x 1053 x 1053 x 1053 x 1053 x 1053 x 1053 x 1053 x 1053 x 1053 x 1053 x 1053 = 1.192784e+145 (rounded, scientific notation form)

(no calculator! )

-3 + 1.192784e+145 = (1.192784e+145 - 3.)

hope this .

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Help ASAP. Thank you! Find the area of the shaded region.
80°
5 cm
A=[?] cm2

Ответ:

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