HELP ASAP TIMED
PLEASE Find the value of the expression. d 27a^0c^3 for a= 2/3 , c=−1/3

-1

Step-by-step explanation:

27a^0c^3

27(2/3)^0(-1/3)^3

Apply the product rule to 2/3.

27(2^0/3^0)(-1/3)^3

Anything raised to 0 is 1.

27(1/3^0)(-1/3)^3

Anything raised to 0 is 1.

27(1/1)(-1/3)^3

Divide 1 by 1.

27 x 1(-1/3)^3

Multiply 27 by 1.

27(-1/3)^3

Apply the product rule to -1/3.

27[(-1)^3(1/3)^3]

Apply the product rule to 1/3.

27[(-1)^3(1^3/3^3)]

Raise -1 to the power of 3.

27(-1^3/3^3)

One to any power is one.

27(-1/3^3)

Raise 3 to the power of 3.

27(-1/27)

Move the leading negative in -1/27 into the numerator.

27(-1/27)

Cancel the common factor and rewrite the expression.

-1

We are given with the data of a parabola with vertex at (2, 2) and directrix at y  = 2.5. the formua should be ax^2 + b x + c = y because of the directrix. 

(x-h)^2 = 4a (y-k)
(x-2)^2 =4a (y-2) 
a is the equidistant distance from focus to vertex and from vertex to directrix that is equal to -0.5
then the  answer is 
(x-2)^2 =-0.5*4 (y-2) 
x2 - 4x + 4 = -2y +4
x2-4x+2y = 0

answer is C