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squiddddplop

13.01.2022

Mathematics

The point-slope form:

$y-y_1=m(x-x_1)\\\\m=\dfrac{y_2-y_1}{x_2-x_1}$

We have the points (2, 2) and (0, -4). Substitute:

$m=\dfrac{-4-2}{0-2}=\dfrac{-6}{-2}=3\\\\y-2=3(x-2)$

The standard form:

Ax+By=C

y-2=3(x-2) use distributive property

y-2=3x-6 add 6 to both sides

y+4=3x subtract y from both sides

4=3x-y

3x - y = 4

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