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Greekfreak
02.03.2022 •
Mathematics
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Hitunglah nilai determinan dari fungsi kuadrat berikut.
1.) 8x² + 7x + 10 = 0
2.) 2x² + 10x + 10 = 5
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Ответ:
Ingat rumus determinan fungsi kuadrat yaitu :
Maka, Kita kembali jawab soalnya.
⏩Nomor (1) :
»8x² + 7x + 10 = 0
Didapatkan nilai² a, b, dan c yaitu :
a = 8 | b = 7 | c = 10Maka, nilai determinannya adalah
D = b² - 4ac D = 7² - 4(8)(10) D = 49 - 4(80) D = 49 - 320 D = -271✅⏩Nomor (2) ;
»2x² + 10x + 10 = 5
»2x² + 10x + 10 - 5 = 0
»2x² + 10x + 5 = 0
Didapatkan nilai² a, b, dan c yaitu :
a = 2 | b = 10 | c = 5Maka, nilai determinannya adalah
D = b² - 4ac D = 10² - 4(2)(5) D = 100 - 4(10) D = 100 - 40 D = 60✅Ответ:
Determinant be D
#2
Ответ:
10= 5 plus 5
Step-by-step explanation: