Mathematics: Help me please this is due tonight! Here is a photo of the problem. I’m a little blank on my math tonight, any help is appreciated!

On e2020 the answer is B. Hope this helps....

Help me please this is due tonight! Here is a photo

Ответ:

mamdouh2893

14.05.2021

Mathematics

9514 1404 393

Step-by-step explanation:

The applicable rules of exponents are ...

(a^b)(a^c) = a^(b+c)

(ab)^c = (a^c)(b^c)

(a^b)^c = a^(bc)

Using these rules, along with the distributive property, we can simplify the given expression.

$\displaystyle 9a^3b^6(3a^3b^2+7a^2b^2)-(5a^4b^4)^2\\\\=\displaystyle 9a^3b^6(3a^3b^2+7a^2b^2)-(5^2a^{4\cdot2}b^{4\cdot2})\\\\=(9)(3)a^{3+3}b^{6+2}+(9)(7)a^{3+2}b^{6+2}-25a^8b^8=27a^6b^8+63a^5b^8-25a^8b^8\\\\=\boxed{-25a^8b^8+27a^6b^8+63a^5b^8}\qquad\text{matches A}$

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Help me please this is due tonight! Here is a photo of the problem. I’m a little blank on my math tonight, any help is appreciated!

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