Help me plz, i'll mark brainiest

1. y=ax^2+bx+c, where a,b, and c are real numbers and a doesn't equal zero

2. Parabola

3. Opens upward

4. Opens downward

5. Vertex

6. Axis of Symmetry

7. Zeros, roots, or x-intercepts

8. You are already given the function so

Step 1: FInd Axis of Symmetry

Equation for Axis of Symmetry: x= - b/2a

Step 2: Find Vertex

- The vertex will be on the Axis of Symmetry, so plug in x then find y.

Equation for Vertex: Ex. The vertex is (-5) which is x now we find y by plugging in -5 whenever we see an X. f(x) = -(-5)^2 - 10(-5)-25=0 our vertex would be (-5,0)

Step 3: Draw your coordinates plane and "dash in" the axis of symmetry. Then plot your vertex

Step 4: Plot your y-intercept and the point symmetrical to it. The y-intercept is "c"

Step 5: Find at least other point on the parabola and draw the curve.

Step-by-step explanation:

we know that

The ellipse has directrices at > given

The directrices has equation:

where e is the eccentricity of the ellipse.

so

> equation A

Remember that the foci are given by:

In this problem

The foci are at (0,2) and (0,-2)

so

> equation B

Solve the system of equations A and B

substitute equation A in equation B

Find the value of a

We know,

Substituting the values, we get

The equation of the ellipse is given by:

we have

substitute

therefore

x squared over 4 plus y squared over 8 equals 1