Help me round to the nearest tenth 5x^2-27=6x

-1.8,3

Step-by-step explanation:

This type of problem often results in two answers for X, and to get it, I often like to rearrange the formula to look like this: 5x^2-6x-27. There are various ways to answer this question, but since this is a quadratic equation, I commend using the quadratic formula! It may look scary, but it is actually really simple. I will attach a picture of this formula for reference when you need it.

looking at our modified formula, a= 5, b=-6, and c= -27. With these values in mind, you can go ahead and plug them in the formula. So it will look like (6±√(-6)²-4(5)(-27) )÷2(5).

Let’s break this down a bit, what this formula is saying is that you’ll have 2 operations to do now, the first one will look like this:

, this will result in 3, which is one of your values for x

the second operation will be exactly the same, but instead of adding 6 to the square root of 576 (pssst, it is 24 btw), you will be subtracting. This second operation once done will result in -1.8, which is rounded to the nearest tenth!

t > 8

Step-by-step explanation:

Given that :

Initial volume = 16 litres

Addition rate = 4 litres per minute

Target volume > 48 litres

Let number of minute for which water is added to achieve these = t

Mathematically,

Initial volume + (addition rate * t) > target volume

16 + 4t > 48

Collect like terms

4t > 48 - 16

4t > 32

Divide both sides by 4

4t/4 > 32/4

t > 8

Laura will need add water at 4 Litre per minute rate for more than 8 minutes