Mathematics: Help urgently wanted Find x

where is the question 0-0Step-by-step explanation:...

Help urgently wanted Find x - id7221496, khalfani0268

leem6

31.01.2022

$\boxed{ \bold{x = 4.54}}$

Step-by-step explanation:

$\sf{Given}$

$\sf{hypotenuse = 5}$

$\sf{base = 2.1}$

$\sf{perpendicular = x}$

Now, Let's find the value of x

Using Pythagoras theorem

$\sf{ {h}^{2} = {p}^{2} + {b}^{2} }$

Plug the values

⇒ $\sf{ {5}^{2} = {x}^{2} + {2.1}^{2} }$

Evaluate the power

⇒ $\sf{25 = {x}^{2} + 4.41}$

Swap the sides of the equation

⇒ $\sf{ {x}^{2} + 4.41 = 25}$

Move constant to R.H.S and change it's sign

⇒ $\sf{ {x}^{2} = 25 - 4.41}$

Calculate the difference

⇒ $\sf{ {x}^{2} = 20.59}$

Squaring on both sides

⇒ $\sf{x = 4.54}$

Hope I helped!

Best regards!!

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