Mathematics: Help with all 3 PLEASE urgent.

Help with all 3 PLEASE urgent. - id312010809, coco9972

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huddyxo

01.12.2021

A) sin 120=sin (180-60)=sin 60= $\frac{ \sqrt{3} }{2}$ (It lies on second quadrant where sin is +ve)
B) tan (150)=tan(180-30)=-tan30= $\frac{-1}{ \sqrt{3} }$ (It lies on second quadrant where tan is -ve)
C) cos (-135)=cos (135)=cos (180-45)=-cos (45)= $\frac{-1}{ \sqrt{2} }$ (It lies on second quadrant where cos is -ve)
D) sec (300)=sec (360-60)=sec(60)=2 (It lies on fourth quadrant where sec is +ve)
E) sin (240)=sin(180-(-60))=sin(-60)=-sin (60)= $\frac{- \sqrt{3} }{2}$
(It lies on third quadrant where sin is -ve)
F) cos (330)=cos(360-30)=cos(30)= $\frac{ \sqrt{3} }{2}$
(It lies on fourth quadrant where cos is +ve)
sin (240)- cos (330)= $- \sqrt{3}$

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Help with all 3 PLEASE urgent.

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