Hobby shop is selling model cars and model trucks for 50% off this week. at the sale price, you can buy one car and one truck for $13.00. also at the sale price, you can buy 4 trucks and 2 cars for $42.00. what is the sale price and the original price of the model car and the model truck?

The truck original price is $16.00 and the car price is $5.00.

The truck sale price is $8.00 and the car price is $10.00.

Step-by-step explanation:

We need to find the original price of the truck (T) and car (C)

Sale price of the truck is 50% so that means it is half the original price.

Now let's see the equations we can come up with there:

At sale price:

We can solve this through substitution.

Using the first equation, we can come up with an equation for one of the missing variables.

We can use this equation on the second one, to solve for one variable.

The sale price of the model truck is $8.00.

Now can use this on the first equation again.

The sale price of the model car is $5.00.

Because it is 50% off on both models, the original price is twice the sale price. So we can solve it by multiplying the sale prices by 2.

Original price of model truck: $8.00 x 2 = $16.00

Original price of model car: $5.00 x 2 = $10.00

B

Step-by-step explanation:

First, let's rearrange the given equation into something more recognizable. If we add 13 to both sides, we now have the polynomial . We can now use the quadratic formula to solve.

Remember that the quadratic formula is

Substitute the numbers from the equation into the formula.

Simplify:

Here, I'm going to assume that there was a mistype in option B because if we divide out the 2 we end up with .

Hope this helps!