Mathematics: Hot dogs come in packages of 10. Hot dog buns come in packages of 8. How many hot dogs and hot dog buns will Mr. Deeks buy so that he has one bun for every hot dog?

Step-by-step explanation:Consider the given matrixLet matrix B isIt is given thatOn comparing corresponding elements of both matrices, we getTherefore, the required values are ....

Hot dogs come in packages of 10. Hot dog buns come

Ответ:

guko

27.01.2022

Mathematics

10 = 2 ⋅ 5 LCM = 2 ⋅ 2 ⋅ 2 ⋅ 5

8 = 2 ⋅ 2 ⋅ 2 =40

40 ÷ 10 = 4 packages of hot dogs

40 ÷ 8 = 5 packages of hot dog buns

You must buy 4 packages of hot dogs

and 5 packages of hot dog buns.

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Ответ:

blxxmgrxcie

27.01.2022

Mathematics

He will buy 4 packages of hot dogs and 5 packages of hot dog buns.

Step-by-step explanation:

First, we must find the common multiple of 10 and 8, which is 40.

Next, since 10 × 4 = 40, and 8 × 5 = 40,

He will buy 4 packages of hot dogs and 5 packages of hot dog buns.

Hope this helps!

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Ответ:

YoungLarQ

27.01.2023

Mathematics

$b_{11}=9,b_{12}=-2,b_{13}=3,b_{21}=2,b_{22}=17,b_{23}=0,b_{31}=3,b_{32}=22,b_{33}=8$

Step-by-step explanation:

Consider the given matrix

$A=\left[\begin{array}{ccc}9&-2&3\\2&17&0\\3&22&8\end{array}\right]$

Let matrix B is

$B=\left[\begin{array}{ccc}b_{11}&b_{12}&b_{13}\\b_{21}&b_{22}&b_{23}\\b_{31}&b_{32}&b_{33}\end{array}\right]$

It is given that

A=B

$\left[\begin{array}{ccc}9&-2&3\\2&17&0\\3&22&8\end{array}\right]=\left[\begin{array}{ccc}b_{11}&b_{12}&b_{13}\\b_{21}&b_{22}&b_{23}\\b_{31}&b_{32}&b_{33}\end{array}\right]$