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jimmyjimjim
16.02.2021 •
Mathematics
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Ответ:
yay
Step-by-step explanation:
thanks
Ответ:
thank u
Step-by-step explanation:
Ответ:
At t = 2 minutes, remaining quantity of the radioactive element is 12.5 mg.
Step-by-step explanation:
To get the answer of this question we will solve this further with the help of the equation![A_{t}=A_{0}e^{-kt}](/tpl/images/0439/4591/fdbb9.png)
where k = decay constant
t = time for decay
From the graph attached we can say that 50 mg of a radioactive element remained half in 1 minute.
So the equation becomes
Now we take natural log on both the sides of the equation
ln50 = ln[25.![e^{-k}](/tpl/images/0439/4591/a7cbe.png)
3.912 = ln25 +![ln(e^{-k})](/tpl/images/0439/4591/83f2c.png)
3.912 = 3.219 + (-k)lne
3.912 - 3.219 = -k [since lne = 1]
0.693 = -k
k = -0.693
Now we will calculate the remaining quantity of the element after 2 minutes
=![50.e^{-1.386}](/tpl/images/0439/4591/59d08.png)
=![\frac{50}{e^{1.386}}](/tpl/images/0439/4591/6c091.png)
=![\frac{50}{3.9988}](/tpl/images/0439/4591/506d1.png)
= 12.50 mg
Now we confirm this value from the graph.
At t = 2 minutes, remaining quantity of the radioactive element is 12.5 mg.