srgrace9948
07.07.2019 •
Mathematics
How do i factor trig functions? i am stuck on how to factor out equations like 1+sinx-cos2x=0 i am confused on where to go from here to solve the equation. pls .
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Ответ:
Use cos2x =1-2sin^2x
1+sinx- (1-2sin^2x) = 1+ sinx -1+2sin^2x
=sinx+2sin^2x=sinx(1+2sinx)
Therefore
Either sinx=0 or 1+ sin2x =0
X=npi or sin2x=-1
Sin2x=sin 3pi/2
2x= npi +(-1)^n3pi/2
x=npi/2 + (-1)^n 3pi/4
Ответ:
okay
Step-by-step explanation: