KhaliylTestman
16.07.2020 •
Mathematics
How do I solve this problem?
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Ответ:
Ответ:
45 g de oxido de hierro (III) liberarán 18.9 L de CO₂
Step-by-step explanation:
La reaccion quimica es la siguiente:
Fe₂O₃ (s) + 3CO (g) → 2Fe (s) + 3CO₂ (g)
1 mol de oxido de hierro (III), reacciona con 3 moles de monoxido de carbono para liberar 3 moles de CO₂ y 2 moles de Fe sólido.
Pasamos la masa de F₂O₃ a moles:
159.6 g . 1 mol /159.7g = 1 mol de oxido
Entonces, aplicamos la regla de tres:
1 mol de oxido produce 3 moles de dioxido de carbono, indudablemente eso será lo que formemos de producto, por lo tanto 3 moles de CO₂ estan ocupando 67.2 litros.
Ahora calculamos los nuevos moles:
45g . 1 mol /159.7 g = 0.282 moles
Aplicamos la regla de tres:
Si un mol de oxido produce 3 moles de CO₂
0.282 moles producen (0.82 . 3 ) = 0.845 moles de CO₂
Como tenemos menos moles de gas, el volumen ocupado sera mayor, hacemos la regla de tres:
Si 3 moles de CO₂ ocupan 67.2 litros
0.845 moles ocuparan (0.845 . 67.2/ 3 ) = 18.9 litros