How do you add all even numbers that are less than 123?

The formula for the sum of the first n positive evens is:

. Your question is equivalent to what is the sum of the first 61 even positive integers.

Step-by-step explanation:

122 is the highest even less than 123.

If we solve 2n=122 we can find what number term 122 is in the sequence of positive even numbers.

2n=122

Divide both sides by 2:

n=61

So 122 is the 61st positive even integer. This means we are adding 61 positive even integers.

2(1)+2(2)+2(3)+2(4)+2(5)+2(6)+..........+2(61)

Factor out out 2:

2(1+2+3+4+5+6+...+61)

We could write in summation notation if you prefer:

There is a formula for computing the following:

So we have the following:

So if you wanted to know the sum of the first n even numbers it is:

.

Examples:

The sum of the first 4 positive even numbers:

Now let's put our formula to the test:

The sum of the first 10 positive even numbers:

Now let's put out formula to the test again:

So as you can see the formula works.

Let me know if you want me to actually prove with mathematical induction.

The fraction 0/4 does represent something. What it represents is zero. Suppose that I have 12 pencils to distribute to 4 students so that each student gets the same number of pencils. How many pencils do I give to each student? This is the classic division problem.

Hope this helps, have a great day, have a great weekend and stay safe!

Also Happy Halloween! :) :D :3