How do you factor this quadratic?
6x^2 + x - 2

Break expression into groups such as for formula ax^2+bx+c, find u and v such that u*v=a*c and u+v=b. In this problem, next step is (6x^2-3x)+ (4x-2). Now factor out 3x from (6x^2-3x)= 3x(2x-1). Now factor out 2 from (4x-2)= 2 (2x-1).
Now you have 3x (2x-1) +2 (2x-1) so factor out common term of (2x-1).Thus, the final answer is (3x+2)(2x-1).

(483.981 ; 504.019)

Step-by-step explanation:

Given :

σ = 100

Sample size, n = 661

xbar = 494

We use the Z distribution since we are working with the population standard deviation ;

C.I = xbar ± (Zcritical * σ/√n)

Zcritical at 99% = 2.576

C.I = 494 ± (2.576 * 100/√661)

C.I = 494 ± 10.019

Lower boundary = (494−10.019) = 483.981

Upper boundary = (494+10.019) = 504.019

C.I = (483.981 ; 504.019)