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cristabean87
02.07.2019 •
Mathematics
How do you solve for n^3 + 3n^2 + n - 33 = 0?
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Ответ:
one real root: n ≈ 2.38450287889
Step-by-step explanation:
My favorite solution method for higher-degree polynomials is to use a graphing calculator.
Descartes' rule of signs tells you the one sign change among coefficients means there will be one positive real root. A graph shows you it is about 2.4, hence irrational (not a divisor of 33, so not rational).
You can use a cubic formula to find an explicit expression for the root, or you can find its value using any of several iteration methods. The attachment shows Newton's method iteration being used to refine the graph value of 2.385 to the more accurate 2.38450287889.
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Factoring that root from the cubic results in a quadratic with irrational coefficients. Its vertex form is approximately ...
y = (n +2.692)² + 6.591
Hence, the complex roots will be near -2.692±i√6.591.
_____
There are formulas for the roots of a cubic. The formula tells you the real root for this cubic is ...
n = 2√(2/3)cosh(1/3·arccosh(24√(3/2))) -1 ≈ 2.38450287889
Ответ:
sure
i wannna laugh too
Step-by-step explanation: