Mathematics: How do you solve this using substitution Y=18x-40 Y=10x-16

How do you solve this using substitution Y=18x-40 - id184011820621, lindseyklewis1p56uvi

dezmondpowell

09.03.2021

point form: (3, 14) equation form: x=3, y=14

Step-by-step explanation:

if the equations are y=18x-40 and y=10x-16 solve y for 18x-40 by substituting 18x-40 for the y in y=10x-16.

18x-40=10x-16

18x-40+-10x=10x-16+-10x

8x-40=-16

8x-40+40=-16+40

8x=24

8x/8=24/8

x=3

then substitute 3 for the x in y=18x-40

y=18(3)-40

y=14

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anaalashay

01.11.2020

Antideritiive
antideritive of x^n

is $\frac{x^{n+1}}{n+1}$
antiderititve of a constant is that constant times x
so

antideritive of x^2

is $\frac{x^{2+1}}{2+1}=\frac{x^{3}}{3}$
andtideritivee of 4 is 4x

total is
$y= \frac{x^3}{3}+4x+C$

D is answer

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