How do you write an equation in point slope form given (9,0) and (6,-1)?

First, I have to calculate the slope (m),

m= (y2-y1)/(x2-x1) = (0+1)/(9-6) = 1/3

now, point slope form would be: y = 1/3 (x-9)

(Brainle pl)

10

explaniion:

given that:

(2x^9y^n)(4x^2y^10)=8x^11y^20

the value of n that will make the inequality true will be found as follows;

(2x^9y^n)(4x^2y^10)=8x^11y^(n+10)

thus;

8x^11y^(n+10)=8x^11y^20

dividing through by 8x^11 we get;

y^(n+10)=y^20

introducing the natural logs we get;

(n+10)lny=20lny

lny will cancel out and we shall remain with;

n+10=20

thus

n=20-10

n=10

the answer is n=10