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missayers172
04.02.2020 •
Mathematics
How does the volume of a cone change when the radius is quadrupled and the height id reduced to 1/5 of the original size?
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Ответ:
V = A x h = πr²h
Now, if the radius is quadrupled and the height is reduced to 1/5, the equation will be,
V2 = π(4r)²(1/5 h) = π(3.2)r²h
Thus, the second volume would be 3.2 time the first volume.
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