![jamiria38](/avatars/48662.jpg)
jamiria38
29.08.2019 •
Mathematics
How i do this someone ples i need with 25 and 27.
Solved
Show answers
More tips
- L Leisure and Entertainment How to Find a Phone Number by Address: The Ultimate Guide...
- P Philosophy How to Properly Create a Vision Board?...
- C Computers and Internet What is Web 2.0 and How Does it Work?...
- S Style and Beauty Is Photoepilation the Solution to Unwanted Hair Forever?...
- O Other What is a Disk Emulsifier and How Does it Work?...
- F Family and Home What does a newborn need?...
- F Family and Home Choosing the Right Car Seat for Your Child: Tips and Recommendations...
- F Food and Cooking How to Get Reconfirmation of Registration?...
- C Computers and Internet How to Get Rid of Spam in ICQ?...
- A Art and Culture Who Said The Less We Love a Woman, the More She Likes Us ?...
Answers on questions: Mathematics
- M Mathematics The graph of F(x) = (3) below models the value of a piece of office equipment 1.3 1.1 0.9 0.7 0.5 0.3 0.1 0.1 0.2 0.3 0.4 0.5 0.6 0.8 0.9 1.0 What is they-intercept...
- M Mathematics How many solutions does the nonlinear system of equations graphed below have?...
- M Mathematics Justine wants to factor the expression 16a+40b by finding the gcf. how can you tell if she factors out the correct gcf...
- M Mathematics Fill in the measures of the missing angle- HELP PLS ILL LOVE U FOREVER 33...
- B Biology How do temperature, pressure, and density impact the core of the earth?...
- E English Chopin s protagonist in the story of an hour, louise mallard, utters the words free, free, free after she recieves the news of her husband s death. what theme of...
- C Chemistry PLEASE HELP I WILL GIVE BRAINLEST! what is life about?...
- W World Languages It is estimated that there are nearly 20,000 Deaf or individuals with hearing loss in the Austin Metropolitan Area Riverside/Bay Area in California greater Rochester...
Ответ:
Number 15 is no solution.
Number 27 is that x has to be between -2 or 2.
This could be explained as -2≤x≤2
Ответ:
Once you get the hang of row ops, it's not terribly hard. This does, however, take a lot of arithmetic.
−6x−y−5z=−10
− 5x+6y+4z=−7
2x−3y−2z=3
can be represented by the matrix
-6 -1 -5 -10
-5 6 4 -7
2 -3 -2 3
Our goal is to transform this 3 x 4 matrix so that it ends up looking like:
1 0 0 a
0 1 0 b
0 0 1 c
and the solution you want is the vector (a, b, c) (three numeric values).
I have more or less arbitrarily chosen to start with the third row:
2 -3 -2 3. We want this row to begin with a 1, so we multiply each of the original four digits by (1/2), obtaining 1 -3/2 -2/2 3/2, or 1 -3/2 -1 3/2.
We can present the original matrix in any order without changing its value. Thus, the original
-6 -1 -5 -10
-5 6 4 -7
2 -3 -2 3
becomes
-6 -1 -5 -10
-5 6 4 -7
1 -3/2 -1 3/2
We want that "1" to appear in the upper, left hand corner of the matrix. We are free to interchange rows, so we interchange the first and 3rd rows, obtaining
1 -3/2 -1 3/2
-5 6 4 -7
-6 -1 -5 -10
Next, we manipulate the first row (which begins with 1) so as to get the first element of the 2nd and 3rd rows to be 0.
To achieve this for the 2nd row, we multiply the 1st row by 5, obtaining
5 -15/2 -5 15/2
and then we add this to the existing 2nd row. The result will be an "0"
in the first column:
0 (6-15/2) ( 4-5) (-7+15/2), or 0 -3/2 -1 1/2.
Substitute this new 2nd row for the original 2nd row. We'll now have:
1 -3/2 -1 3/2
0 -3/2 -1 1/2
-6 -1 -5 -10
Now we have to "fix" the 3rd row, so that it starts with a zero (0):
To accomplish this, mult. the first row by 6 and add the resulting new row to the existing 3rd row. Result should be 0 -10 -11 -1, and the revised matrix will be
1 -3/2 -1 3/2
0 -3/2 -1 1/2
0 -10 -11 -1
Next steps involve transforming the 2nd column so that it looks lilke
0
1
0.
To do this, mult. the entire 2nd row by -2/3, Here's the expected result:
0 1 2/3 -1/3
Replace the existing 2nd row with this revised 2nd row:
1 -3/2 -1 3/2
0 -3/2 -1 1/2
0 -10 -11 -1 becomes
1 -3/2 -1 3/2
0 1 2/3 -1/3
0 -10 -11 -1
In the end we want this matrix to look like
1 0 0 a
0 1 0 b
0 0 1 c
and the solution you want is the vector (a, b, c) (three numeric values).
Use this new 2nd row to further fix the 2nd column, so that it looks like
0
1
0.
I ask that you go thru this discussion and work out each set of calculations yourself, to verify what I have done so far. Reply with any questions that arise. We'll find a way to finish this solution.