Aprilbtrippin2004
26.01.2022 •
Mathematics
How is 3 and 4 related to 12 fractions
Solved
Show answers
More tips
- C Computers and Internet Which Phone is Best for Internet Surfing?...
- F Food and Cooking Everything You Need to Know About Pasta...
- C Computers and Internet How to Choose a Monitor?...
- S Style and Beauty How to Get Rid of Peeling Nails: Natural Remedies...
- S Science and Technology Understanding Magnetic Storms: A Guide to This Natural Phenomenon...
- F Family and Home What is Most Important in Men s Lives?...
- G Goods and services Which TV is better - LCD or Plasma?...
- C Computers and Internet Are there special gaming mice?...
- G Goods and services LED-подсветка в LCD-телевизорах: 5 причин, почему она лучше других технологий...
- C Computers and Internet Keep Your Mouse Pad Clean: The Right Way to Clean It?...
Answers on questions: Mathematics
- H Health Soil pollution is caused by the buildup of wastes that can adversely affect human, animal, and plant life....
- B Biology A herblvore needs to find what type of food from its surroundings? Enter your answer...
- M Mathematics 4-5c=6+9(8-7c) State if it has one no or infinite solutions...
- M Mathematics 0.65 amplitude = how many decibels?? help pls i want a siren but theres no details on decibels...
Ответ:
3/4 of 13 is 9
3/4 x 12/1 = (3 x 12) / (4 x 1) = 35/4= 9
The answer is 9
Ответ:
A. The decrease in Car 1 value is constant at 6000 from year to year. Its value can be described by a linear function.
The decrease in Car 2 value is a constant percentage of its current value from year to year. Its value can be described by an exponential function.
B. The slope of the Car 1 function is -6000, and the value is 32000 in year 1, so the value function for Car 1 can be written as
... f(x) = 32000 -6000(x-1)
... f(x) = 38000 -6000x
The value multiplier for Car 2 from year to year is 27455/32300 = 0.85, so the value function for Car 2 can be written as
... f(x) = 32,300·0.85^(x-1)
... f(x) = 38000·0.85^x
C. There is a significant difference in value after 5 years. Car 2 is worth more than double the value of Car 1 in year 5. That year, their values are ...
... car 1: $8000
... car 2: $16861