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testedagent2823
18.12.2020 •
Mathematics
how many 3 digit numbers can be formed using numerals in the set 3,2,7, and 9 if repetition is not allowed?
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Ответ:
We have to look at how many ways to choose 3 numbers and how many ways to arrange those.
In how many ways can we choose 3 digits? That’s going to be 4C3
And in how many ways can we arrange these 3 digits? In 3 *2*1 ways (3!)
Then we multiply both together → 4C3 * 3! =24
There are 24 ways to make 3 digit numbers out of 3,2,7,9.
And in fact when we check:
329 723 237 923
327 729 239 927
379 732 273 937
372 739 279 932
392 792 293 972
397 793 297 973
Step-by-step explanation:
Ответ:
3÷1/2 and 1/2÷3 there is no difference bc they both add up the same as each other