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shy5732
24.07.2019 •
Mathematics
How many different ordered pairs satisfy both x^{2} + y^{2} = 100 and x^{2} + 2y^{2} = 108?
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Ответ:
We know that
As we see there are 4 such pairs:
Ответ:
60 feet
Step-by-step explanation:
The diagonal of a rectangle =root(l^2+b^2)
Therefore,root(36^2+48^2)
. =root(1296+2404)
. =root(3600)=60
correct me if i am wrong