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Treezy11
29.07.2020 •
Mathematics
How many natural 4-digit numbers exist in which all of the digits are even?
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Ответ:
256
Step-by-step explanation:
the first digit cannot be 0, so there are only 4 even numbers
For the second, third, and fourth digits, there are 5 available numbers.
Thus, the number of 4-digit numbers containing only even digits is 4 x 5 x 5 x 5 = 500
2nd place ( hundred place) can also be filled up by 4 number : 2, 4, 6, 8 and same logic applies to 3rd ( 10th ) and 4th( unit) .
so number of ways is 4*4*4*4= 256 ways .
Ответ:
(-7) + (-14) = -21
(-7)*(-14)=98