neariah24
26.09.2019 •
Mathematics
How many real number solutions does the equation have? -8x^2-8x-2=0
1
2
no solutions
or
infinitely many solutions
solve the equation by completing the square. round to the nearest hundredth. x^2+6x=-7
4.41,1.59
-4.41,1.59
-4.41,-1.59
4.41,-1.59
and the last one is
solve the systems of equations algebraically. show all of your steps.
y=x^2+2x
y=3x+20
Solved
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Ответ:
I)
1 solution with multiplicity 2
(2x+1)²=0
II) ANSWER C (-4.41, -1.59)
-3-√2 and -3+√2
III)
y=x²+2x
y=3x+20
==>x²+2x=3x+20
==>x²-x-20=
Δ=1+4*20=81=9²
(x=(1-9)/2=-4 and y= 3*(-4)+20=8 ) or (x=(1+9)/2=5 and y=3*5+20=35)
Ответ: