How much material is needed to construct a triangular tent that is 24 feet wide, 5 feet tall, and 20 feet long with side measurements of 13 feet? 816 square feet 1024 square feet 1120 square feet 1392 square feet

The answer is " 1120 square feet. ".
Total surface area of a triangular prism = width x height +(sum of sides + width) x length and here;
width = 24
height = 5
sides = 13
length = 20
= (24 x 5) + (13 + 13 + 24) x 20
= 120 + (50 x 20)
= 120 + 1000
= 1120 square feet. 

Let x be the missing number.

The equation is:

● 2(x+3)^2 = 98

Divide both sides by 2

●(2/2)×(x+3)^2 = 98/2

● (x+3)^2 = 49

● (x+3) = -√49 or (x+3) = √49

● (x+3) = -7 or (x+3) = 7

● x = -7–3 or x = 7–3

● x = -10 or x = 4

So x has two values.

x = {4, -10}